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1015540422241 is a prime number
BaseRepresentation
bin11101100011100101110…
…11010001011001100001
310121002021202110200010011
432301302323101121201
5113114311322002431
62054311031404521
7133241016106342
oct16616273213141
93532252420104
101015540422241
11361763103164
1214499a523741
13749c3a80767
143721c3460c9
151b63ac2acb1
hexec72ed1661

1015540422241 has 2 divisors, whose sum is σ = 1015540422242. Its totient is φ = 1015540422240.

The previous prime is 1015540422227. The next prime is 1015540422293. The reversal of 1015540422241 is 1422240455101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 870729730641 + 144810691600 = 933129^2 + 380540^2 .

It is a cyclic number.

It is not a de Polignac number, because 1015540422241 - 233 = 1006950487649 is a prime.

It is not a weakly prime, because it can be changed into another prime (1015540222241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507770211120 + 507770211121.

It is an arithmetic number, because the mean of its divisors is an integer number (507770211121).

Almost surely, 21015540422241 is an apocalyptic number.

It is an amenable number.

1015540422241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1015540422241 is an equidigital number, since it uses as much as digits as its factorization.

1015540422241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12800, while the sum is 31.

Adding to 1015540422241 its reverse (1422240455101), we get a palindrome (2437780877342).

The spelling of 1015540422241 in words is "one trillion, fifteen billion, five hundred forty million, four hundred twenty-two thousand, two hundred forty-one".