Base | Representation |
---|---|
bin | 11101100011100101110… |
… | …11010001011001100001 |
3 | 10121002021202110200010011 |
4 | 32301302323101121201 |
5 | 113114311322002431 |
6 | 2054311031404521 |
7 | 133241016106342 |
oct | 16616273213141 |
9 | 3532252420104 |
10 | 1015540422241 |
11 | 361763103164 |
12 | 14499a523741 |
13 | 749c3a80767 |
14 | 3721c3460c9 |
15 | 1b63ac2acb1 |
hex | ec72ed1661 |
1015540422241 has 2 divisors, whose sum is σ = 1015540422242. Its totient is φ = 1015540422240.
The previous prime is 1015540422227. The next prime is 1015540422293. The reversal of 1015540422241 is 1422240455101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 870729730641 + 144810691600 = 933129^2 + 380540^2 .
It is a cyclic number.
It is not a de Polignac number, because 1015540422241 - 233 = 1006950487649 is a prime.
It is not a weakly prime, because it can be changed into another prime (1015540222241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507770211120 + 507770211121.
It is an arithmetic number, because the mean of its divisors is an integer number (507770211121).
Almost surely, 21015540422241 is an apocalyptic number.
It is an amenable number.
1015540422241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1015540422241 is an equidigital number, since it uses as much as digits as its factorization.
1015540422241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 1015540422241 its reverse (1422240455101), we get a palindrome (2437780877342).
The spelling of 1015540422241 in words is "one trillion, fifteen billion, five hundred forty million, four hundred twenty-two thousand, two hundred forty-one".
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