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10158927433 is a prime number
BaseRepresentation
bin10010111011000010…
…01110111001001001
3222012222210222120121
421131201032321021
5131301141134213
64400021023241
7506514313144
oct113541167111
928188728517
1010158927433
1143434a45a6
121b76254b21
13c5b8c3985
146c52d305b
153e6d0288d
hex25d84ee49

10158927433 has 2 divisors, whose sum is σ = 10158927434. Its totient is φ = 10158927432.

The previous prime is 10158927413. The next prime is 10158927463. The reversal of 10158927433 is 33472985101.

10158927433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6718753024 + 3440174409 = 81968^2 + 58653^2 .

It is a cyclic number.

It is not a de Polignac number, because 10158927433 - 213 = 10158919241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10158927433.

It is not a weakly prime, because it can be changed into another prime (10158927403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5079463716 + 5079463717.

It is an arithmetic number, because the mean of its divisors is an integer number (5079463717).

Almost surely, 210158927433 is an apocalyptic number.

It is an amenable number.

10158927433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10158927433 is an equidigital number, since it uses as much as digits as its factorization.

10158927433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 43.

The spelling of 10158927433 in words is "ten billion, one hundred fifty-eight million, nine hundred twenty-seven thousand, four hundred thirty-three".