Base | Representation |
---|---|
bin | 10111000111010010101001… |
… | …101101110110110010000111 |
3 | 111022221020020201100201211002 |
4 | 113013102221231312302013 |
5 | 101311013230113111403 |
6 | 1000112103303403515 |
7 | 30261261515166620 |
oct | 2707225155666207 |
9 | 438836221321732 |
10 | 101656133332103 |
11 | 2a433140106919 |
12 | b49978145359b |
13 | 44951946bba9c |
14 | 1b1627c628a47 |
15 | bb4498e1c188 |
hex | 5c74a9b76c87 |
101656133332103 has 4 divisors (see below), whose sum is σ = 116178438093840. Its totient is φ = 87133828570368.
The previous prime is 101656133332051. The next prime is 101656133332139. The reversal of 101656133332103 is 301233331656101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 101656133332103 - 212 = 101656133328007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101656133332603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7261152380858 + ... + 7261152380871.
It is an arithmetic number, because the mean of its divisors is an integer number (29044609523460).
Almost surely, 2101656133332103 is an apocalyptic number.
101656133332103 is a deficient number, since it is larger than the sum of its proper divisors (14522304761737).
101656133332103 is an equidigital number, since it uses as much as digits as its factorization.
101656133332103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14522304761736.
The product of its (nonzero) digits is 87480, while the sum is 38.
Adding to 101656133332103 its reverse (301233331656101), we get a palindrome (402889464988204).
The spelling of 101656133332103 in words is "one hundred one trillion, six hundred fifty-six billion, one hundred thirty-three million, three hundred thirty-two thousand, one hundred three".
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