101697131 has 2 divisors, whose sum is σ = 101697132. Its totient is φ = 101697130.

The previous prime is 101697083. The next prime is 101697149. The reversal of 101697131 is 131796101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101697131 is a prime.

It is a super-2 number, since 2×101697131² = 20684612907262322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101697094 and 101697103.

It is not a weakly prime, because it can be changed into another prime (101697931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50848565 + 50848566.

It is an arithmetic number, because the mean of its divisors is an integer number (50848566).

Almost surely, 2^101697131 is an apocalyptic number.

101697131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101697131 is an equidigital number, since it uses as much as digits as its factorization.

101697131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1134, while the sum is 29.

The square root of 101697131 is about 10084.4995413754. The cubic root of 101697131 is about 466.7699622248.

The spelling of 101697131 in words is "one hundred one million, six hundred ninety-seven thousand, one hundred thirty-one".