Base | Representation |
---|---|
bin | 11101100111101101010… |
… | …00000011000000000001 |
3 | 10121021222202010120202001 |
4 | 32303312220003000001 |
5 | 113133322443200131 |
6 | 2055314202024001 |
7 | 133346536023262 |
oct | 16636650030001 |
9 | 3537882116661 |
10 | 1017749975041 |
11 | 362697367958 |
12 | 1452b64a8001 |
13 | 74c86778257 |
14 | 3738b98c969 |
15 | 1b719bd3261 |
hex | ecf6a03001 |
1017749975041 has 2 divisors, whose sum is σ = 1017749975042. Its totient is φ = 1017749975040.
The previous prime is 1017749974993. The next prime is 1017749975093. The reversal of 1017749975041 is 1405799477101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 761186451600 + 256563523441 = 872460^2 + 506521^2 .
It is a cyclic number.
It is not a de Polignac number, because 1017749975041 - 215 = 1017749942273 is a prime.
It is a super-2 number, since 2×10177499750412 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1017749925041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 508874987520 + 508874987521.
It is an arithmetic number, because the mean of its divisors is an integer number (508874987521).
Almost surely, 21017749975041 is an apocalyptic number.
It is an amenable number.
1017749975041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1017749975041 is an equidigital number, since it uses as much as digits as its factorization.
1017749975041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2222640, while the sum is 55.
The spelling of 1017749975041 in words is "one trillion, seventeen billion, seven hundred forty-nine million, nine hundred seventy-five thousand, forty-one".
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