Search a number
-
+
10183113 = 328912713
BaseRepresentation
bin100110110110…
…000111001001
3201011100121100
4212312013021
510101324423
61002132013
7152361243
oct46660711
921140540
1010183113
1158257a6
1234b1009
132157015
1414d1093
15d62343
hex9b61c9

10183113 has 12 divisors (see below), whose sum is σ = 14875380. Its totient is φ = 6711936.

The previous prime is 10183081. The next prime is 10183141. The reversal of 10183113 is 31138101.

It is a happy number.

10183113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 6215049 + 3968064 = 2493^2 + 1992^2 .

It is not a de Polignac number, because 10183113 - 25 = 10183081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10183193) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5556 + ... + 7157.

It is an arithmetic number, because the mean of its divisors is an integer number (1239615).

Almost surely, 210183113 is an apocalyptic number.

It is an amenable number.

10183113 is a deficient number, since it is larger than the sum of its proper divisors (4692267).

10183113 is a wasteful number, since it uses less digits than its factorization.

10183113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12808 (or 12805 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

The square root of 10183113 is about 3191.0990269811. The cubic root of 10183113 is about 216.7505397831.

It can be divided in two parts, 10183 and 113, that added together give a triangular number (10296 = T143).

The spelling of 10183113 in words is "ten million, one hundred eighty-three thousand, one hundred thirteen".

Divisors: 1 3 9 89 267 801 12713 38139 114417 1131457 3394371 10183113