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102013221329953 is a prime number
BaseRepresentation
bin10111001100011111001101…
…110100011101110000100001
3111101012100221210102112022221
4113030133031310131300201
5101332341034130024303
61000544121002431041
730326132503120633
oct2714371564356041
9441170853375287
10102013221329953
112a560622a6392a
12b536a19502481
1344bca61893b7b
141b296755a2a53
15bbd8e836d4bd
hex5cc7cdd1dc21

102013221329953 has 2 divisors, whose sum is σ = 102013221329954. Its totient is φ = 102013221329952.

The previous prime is 102013221329941. The next prime is 102013221330023. The reversal of 102013221329953 is 359923122310201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73973898252864 + 28039323077089 = 8600808^2 + 5295217^2 .

It is an emirp because it is prime and its reverse (359923122310201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102013221329953 - 29 = 102013221329441 is a prime.

It is a super-2 number, since 2×1020132213299532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (102013221329153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51006610664976 + 51006610664977.

It is an arithmetic number, because the mean of its divisors is an integer number (51006610664977).

Almost surely, 2102013221329953 is an apocalyptic number.

It is an amenable number.

102013221329953 is a deficient number, since it is larger than the sum of its proper divisors (1).

102013221329953 is an equidigital number, since it uses as much as digits as its factorization.

102013221329953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 174960, while the sum is 43.

The spelling of 102013221329953 in words is "one hundred two trillion, thirteen billion, two hundred twenty-one million, three hundred twenty-nine thousand, nine hundred fifty-three".