Base | Representation |
---|---|
bin | 1001010001110101011101… |
… | …0011010100111001010001 |
3 | 1100010022011202110202001221 |
4 | 2110131113103110321101 |
5 | 2314122210033341423 |
6 | 33410423431325041 |
7 | 2102033240202655 |
oct | 224352723247121 |
9 | 40108152422057 |
10 | 10202012012113 |
11 | 32837158a6749 |
12 | 1189275220781 |
13 | 5900792693bc |
14 | 273acc514a65 |
15 | 12a59ed4de5d |
hex | 947574d4e51 |
10202012012113 has 2 divisors, whose sum is σ = 10202012012114. Its totient is φ = 10202012012112.
The previous prime is 10202012012107. The next prime is 10202012012123. The reversal of 10202012012113 is 31121021020201.
10202012012113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9844326679489 + 357685332624 = 3137567^2 + 598068^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10202012012113 is a prime.
It is not a weakly prime, because it can be changed into another prime (10202012012123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5101006006056 + 5101006006057.
It is an arithmetic number, because the mean of its divisors is an integer number (5101006006057).
Almost surely, 210202012012113 is an apocalyptic number.
It is an amenable number.
10202012012113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10202012012113 is an equidigital number, since it uses as much as digits as its factorization.
10202012012113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 10202012012113 its reverse (31121021020201), we get a palindrome (41323033032314).
The spelling of 10202012012113 in words is "ten trillion, two hundred two billion, twelve million, twelve thousand, one hundred thirteen".
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