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10202012012113 is a prime number
BaseRepresentation
bin1001010001110101011101…
…0011010100111001010001
31100010022011202110202001221
42110131113103110321101
52314122210033341423
633410423431325041
72102033240202655
oct224352723247121
940108152422057
1010202012012113
1132837158a6749
121189275220781
135900792693bc
14273acc514a65
1512a59ed4de5d
hex947574d4e51

10202012012113 has 2 divisors, whose sum is σ = 10202012012114. Its totient is φ = 10202012012112.

The previous prime is 10202012012107. The next prime is 10202012012123. The reversal of 10202012012113 is 31121021020201.

10202012012113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9844326679489 + 357685332624 = 3137567^2 + 598068^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10202012012113 is a prime.

It is not a weakly prime, because it can be changed into another prime (10202012012123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5101006006056 + 5101006006057.

It is an arithmetic number, because the mean of its divisors is an integer number (5101006006057).

Almost surely, 210202012012113 is an apocalyptic number.

It is an amenable number.

10202012012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10202012012113 is an equidigital number, since it uses as much as digits as its factorization.

10202012012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 10202012012113 its reverse (31121021020201), we get a palindrome (41323033032314).

The spelling of 10202012012113 in words is "ten trillion, two hundred two billion, twelve million, twelve thousand, one hundred thirteen".