Base | Representation |
---|---|
bin | 101111100000011111… |
… | …1011110011101101011 |
3 | 100202100002121022222122 |
4 | 1133000333132131223 |
5 | 3132420130110011 |
6 | 114511315541455 |
7 | 10241126440031 |
oct | 1370077363553 |
9 | 322302538878 |
10 | 102022113131 |
11 | 3a2a3906684 |
12 | 17932bba88b |
13 | 980b729ca3 |
14 | 4d1b834551 |
15 | 29c1a193db |
hex | 17c0fde76b |
102022113131 has 2 divisors, whose sum is σ = 102022113132. Its totient is φ = 102022113130.
The previous prime is 102022113113. The next prime is 102022113139. The reversal of 102022113131 is 131311220201.
Together with previous prime (102022113113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102022113131 - 210 = 102022112107 is a prime.
It is a super-2 number, since 2×1020221131312 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (102022113139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51011056565 + 51011056566.
It is an arithmetic number, because the mean of its divisors is an integer number (51011056566).
Almost surely, 2102022113131 is an apocalyptic number.
102022113131 is a deficient number, since it is larger than the sum of its proper divisors (1).
102022113131 is an equidigital number, since it uses as much as digits as its factorization.
102022113131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 102022113131 its reverse (131311220201), we get a palindrome (233333333332).
The spelling of 102022113131 in words is "one hundred two billion, twenty-two million, one hundred thirteen thousand, one hundred thirty-one".
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