Base | Representation |
---|---|
bin | 10111001100110000101101… |
… | …110110011100100011010001 |
3 | 111101021011110101000022002201 |
4 | 113030300231312130203101 |
5 | 101333143030124044332 |
6 | 1001000505343043201 |
7 | 30330366245030113 |
oct | 2714605566344321 |
9 | 441234411008081 |
10 | 102032012331217 |
11 | 2a568595aa0241 |
12 | b53a5a25a0501 |
13 | 44c1767946427 |
14 | 1b2a5390953b3 |
15 | bbe147dc25e7 |
hex | 5ccc2dd9c8d1 |
102032012331217 has 2 divisors, whose sum is σ = 102032012331218. Its totient is φ = 102032012331216.
The previous prime is 102032012331149. The next prime is 102032012331233. The reversal of 102032012331217 is 712133210230201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95698656239761 + 6333356091456 = 9782569^2 + 2516616^2 .
It is a cyclic number.
It is not a de Polignac number, because 102032012331217 - 27 = 102032012331089 is a prime.
It is not a weakly prime, because it can be changed into another prime (102032012331017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51016006165608 + 51016006165609.
It is an arithmetic number, because the mean of its divisors is an integer number (51016006165609).
Almost surely, 2102032012331217 is an apocalyptic number.
It is an amenable number.
102032012331217 is a deficient number, since it is larger than the sum of its proper divisors (1).
102032012331217 is an equidigital number, since it uses as much as digits as its factorization.
102032012331217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 102032012331217 its reverse (712133210230201), we get a palindrome (814165222561418).
The spelling of 102032012331217 in words is "one hundred two trillion, thirty-two billion, twelve million, three hundred thirty-one thousand, two hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.154 sec. • engine limits •