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10204443131 is a prime number
BaseRepresentation
bin10011000000011101…
…10111000111111011
3222100011110102101012
421200032313013323
5131344314140011
64404324344135
7510606223031
oct114016670773
928304412335
1010204443131
114367162183
121b8954504b
13c6816bc3c
146cb380551
153eace3a8b
hex2603b71fb

10204443131 has 2 divisors, whose sum is σ = 10204443132. Its totient is φ = 10204443130.

The previous prime is 10204443079. The next prime is 10204443181. The reversal of 10204443131 is 13134440201.

It is a strong prime.

It is an emirp because it is prime and its reverse (13134440201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10204443131 - 210 = 10204442107 is a prime.

It is a super-2 number, since 2×102044431312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10204443097 and 10204443106.

It is not a weakly prime, because it can be changed into another prime (10204443181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5102221565 + 5102221566.

It is an arithmetic number, because the mean of its divisors is an integer number (5102221566).

Almost surely, 210204443131 is an apocalyptic number.

10204443131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10204443131 is an equidigital number, since it uses as much as digits as its factorization.

10204443131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 10204443131 its reverse (13134440201), we get a palindrome (23338883332).

The spelling of 10204443131 in words is "ten billion, two hundred four million, four hundred forty-three thousand, one hundred thirty-one".