Base | Representation |
---|---|
bin | 10111001101000110101000… |
… | …001111000100000001010011 |
3 | 111101100102012002022010100111 |
4 | 113031012220033010001103 |
5 | 101334034221323104141 |
6 | 1001015400144102151 |
7 | 30332161300460632 |
oct | 2715065017040123 |
9 | 441312162263314 |
10 | 102055540441171 |
11 | 2a577569aa6509 |
12 | b54306a004957 |
13 | 44c3a47250295 |
14 | 1b2b72bb75519 |
15 | bbea7374e381 |
hex | 5cd1a83c4053 |
102055540441171 has 2 divisors, whose sum is σ = 102055540441172. Its totient is φ = 102055540441170.
The previous prime is 102055540441133. The next prime is 102055540441199. The reversal of 102055540441171 is 171144045550201.
It is a strong prime.
It is an emirp because it is prime and its reverse (171144045550201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 102055540441171 - 241 = 99856517185619 is a prime.
It is not a weakly prime, because it can be changed into another prime (102055540441111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51027770220585 + 51027770220586.
It is an arithmetic number, because the mean of its divisors is an integer number (51027770220586).
Almost surely, 2102055540441171 is an apocalyptic number.
102055540441171 is a deficient number, since it is larger than the sum of its proper divisors (1).
102055540441171 is an equidigital number, since it uses as much as digits as its factorization.
102055540441171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112000, while the sum is 40.
Adding to 102055540441171 its reverse (171144045550201), we get a palindrome (273199585991372).
The spelling of 102055540441171 in words is "one hundred two trillion, fifty-five billion, five hundred forty million, four hundred forty-one thousand, one hundred seventy-one".
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