Base | Representation |
---|---|
bin | 10011000001001000… |
… | …00110111101001011 |
3 | 222100112221101210202 |
4 | 21200210012331023 |
5 | 131402230404003 |
6 | 4405044002415 |
7 | 511004451521 |
oct | 114044067513 |
9 | 28315841722 |
10 | 10210013003 |
11 | 436a316983 |
12 | 1b8b39040b |
13 | c6936c218 |
14 | 6cbdd0311 |
15 | 3eb544088 |
hex | 260906f4b |
10210013003 has 2 divisors, whose sum is σ = 10210013004. Its totient is φ = 10210013002.
The previous prime is 10210012999. The next prime is 10210013057. The reversal of 10210013003 is 30031001201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10210013003 - 22 = 10210012999 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (10210015003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105006501 + 5105006502.
It is an arithmetic number, because the mean of its divisors is an integer number (5105006502).
Almost surely, 210210013003 is an apocalyptic number.
10210013003 is a deficient number, since it is larger than the sum of its proper divisors (1).
10210013003 is an equidigital number, since it uses as much as digits as its factorization.
10210013003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 10210013003 its reverse (30031001201), we get a palindrome (40241014204).
The spelling of 10210013003 in words is "ten billion, two hundred ten million, thirteen thousand, three".
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