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102100332131113 is a prime number
BaseRepresentation
bin10111001101110000010110…
…000001110011001100101001
3111101111200210200202201201211
4113031300112001303030221
5101340302440011143423
61001052124533313121
730335335260531151
oct2715602601631451
9441450720681654
10102100332131113
112a594564813088
12b54b88a7957a1
1344c8034c57824
141b2d97a89b761
15bc0ce5c4110d
hex5cdc16073329

102100332131113 has 2 divisors, whose sum is σ = 102100332131114. Its totient is φ = 102100332131112.

The previous prime is 102100332131089. The next prime is 102100332131143. The reversal of 102100332131113 is 311131233001201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94760334498064 + 7339997633049 = 9734492^2 + 2709243^2 .

It is an emirp because it is prime and its reverse (311131233001201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102100332131113 - 225 = 102100298576681 is a prime.

It is not a weakly prime, because it can be changed into another prime (102100332131143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51050166065556 + 51050166065557.

It is an arithmetic number, because the mean of its divisors is an integer number (51050166065557).

Almost surely, 2102100332131113 is an apocalyptic number.

It is an amenable number.

102100332131113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102100332131113 is an equidigital number, since it uses as much as digits as its factorization.

102100332131113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 102100332131113 its reverse (311131233001201), we get a palindrome (413231565132314).

The spelling of 102100332131113 in words is "one hundred two trillion, one hundred billion, three hundred thirty-two million, one hundred thirty-one thousand, one hundred thirteen".