Base | Representation |
---|---|
bin | 10111001101110010001101… |
… | …110101011001000001110001 |
3 | 111101111212222202221222012202 |
4 | 113031302031311121001301 |
5 | 101340321044042102423 |
6 | 1001053100215032545 |
7 | 30335436135415313 |
oct | 2715621565310161 |
9 | 441455882858182 |
10 | 102102342144113 |
11 | 2a5953a6379653 |
12 | b55014b96b755 |
13 | 44c82954c962c |
14 | 1b2dacb8017b3 |
15 | bc0db2430728 |
hex | 5cdc8dd59071 |
102102342144113 has 2 divisors, whose sum is σ = 102102342144114. Its totient is φ = 102102342144112.
The previous prime is 102102342144109. The next prime is 102102342144119. The reversal of 102102342144113 is 311441243201201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70750775177104 + 31351566967009 = 8411348^2 + 5599247^2 .
It is a cyclic number.
It is not a de Polignac number, because 102102342144113 - 22 = 102102342144109 is a prime.
It is not a weakly prime, because it can be changed into another prime (102102342144119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51051171072056 + 51051171072057.
It is an arithmetic number, because the mean of its divisors is an integer number (51051171072057).
Almost surely, 2102102342144113 is an apocalyptic number.
It is an amenable number.
102102342144113 is a deficient number, since it is larger than the sum of its proper divisors (1).
102102342144113 is an equidigital number, since it uses as much as digits as its factorization.
102102342144113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 102102342144113 its reverse (311441243201201), we get a palindrome (413543585345314).
The spelling of 102102342144113 in words is "one hundred two trillion, one hundred two billion, three hundred forty-two million, one hundred forty-four thousand, one hundred thirteen".
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