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102110022011147 is a prime number
BaseRepresentation
bin10111001101111001010111…
…100101110000100100001011
3111101112121210222222122020112
4113031321113211300210023
5101340432311113324042
61001100410241144535
730336130351254233
oct2715712745604413
9441477728878215
10102110022011147
112a5986874713a7
12b55173392b14b
1344c8c1a612b57
141b30219774cc3
15bc11b1791982
hex5cde5797090b

102110022011147 has 2 divisors, whose sum is σ = 102110022011148. Its totient is φ = 102110022011146.

The previous prime is 102110022011059. The next prime is 102110022011191. The reversal of 102110022011147 is 741110220011201.

It is a strong prime.

It is an emirp because it is prime and its reverse (741110220011201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102110022011147 - 242 = 97711975500043 is a prime.

It is not a weakly prime, because it can be changed into another prime (102110022013147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51055011005573 + 51055011005574.

It is an arithmetic number, because the mean of its divisors is an integer number (51055011005574).

Almost surely, 2102110022011147 is an apocalyptic number.

102110022011147 is a deficient number, since it is larger than the sum of its proper divisors (1).

102110022011147 is an equidigital number, since it uses as much as digits as its factorization.

102110022011147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224, while the sum is 23.

Adding to 102110022011147 its reverse (741110220011201), we get a palindrome (843220242022348).

The spelling of 102110022011147 in words is "one hundred two trillion, one hundred ten billion, twenty-two million, eleven thousand, one hundred forty-seven".