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102111207826897 is a prime number
BaseRepresentation
bin10111001101111010011110…
…010001010010010111010001
3111101112201212122022022122101
4113031322132101102113101
5101340442223200430042
61001101124041240401
730336201630445063
oct2715723621222721
9441481778268571
10102111207826897
112a59913586a315
12b551a04a93101
1344c90791ac089
141b302cd051733
15bc12309296b7
hex5cde9e4525d1

102111207826897 has 2 divisors, whose sum is σ = 102111207826898. Its totient is φ = 102111207826896.

The previous prime is 102111207826883. The next prime is 102111207826913. The reversal of 102111207826897 is 798628702111201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102108680653456 + 2527173441 = 10104884^2 + 50271^2 .

It is a cyclic number.

It is not a de Polignac number, because 102111207826897 - 243 = 93315114804689 is a prime.

It is not a weakly prime, because it can be changed into another prime (102111207826877) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51055603913448 + 51055603913449.

It is an arithmetic number, because the mean of its divisors is an integer number (51055603913449).

Almost surely, 2102111207826897 is an apocalyptic number.

It is an amenable number.

102111207826897 is a deficient number, since it is larger than the sum of its proper divisors (1).

102111207826897 is an equidigital number, since it uses as much as digits as its factorization.

102111207826897 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1354752, while the sum is 55.

The spelling of 102111207826897 in words is "one hundred two trillion, one hundred eleven billion, two hundred seven million, eight hundred twenty-six thousand, eight hundred ninety-seven".