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102111300142135 = 561794237862633
BaseRepresentation
bin10111001101111010100011…
…110001011100010000110111
3111101112202010002000102100021
4113031322203301130100313
5101340442420314022020
61001101141140030011
730336204131222524
oct2715724361342067
9441482102012307
10102111300142135
112a5991829920a9
12b551a2b992307
1344c9092361a8b
141b302db40214b
15bc1238ab21aa
hex5cdea3c5c437

102111300142135 has 16 divisors (see below), whose sum is σ = 126118791987840. Its totient is φ = 79332788471040.

The previous prime is 102111300142109. The next prime is 102111300142139. The reversal of 102111300142135 is 531241003111201.

It is not a de Polignac number, because 102111300142135 - 29 = 102111300141623 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102111300142139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2118907222 + ... + 2118955411.

It is an arithmetic number, because the mean of its divisors is an integer number (7882424499240).

Almost surely, 2102111300142135 is an apocalyptic number.

102111300142135 is a deficient number, since it is larger than the sum of its proper divisors (24007491845705).

102111300142135 is an equidigital number, since it uses as much as digits as its factorization.

102111300142135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4237862778.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 102111300142135 its reverse (531241003111201), we get a palindrome (633352303253336).

The spelling of 102111300142135 in words is "one hundred two trillion, one hundred eleven billion, three hundred million, one hundred forty-two thousand, one hundred thirty-five".

Divisors: 1 5 61 79 305 395 4819 24095 4237862633 21189313165 258509620613 334791148007 1292548103065 1673955740035 20422260028427 102111300142135