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102112022113 is a prime number
BaseRepresentation
bin101111100011001011…
…0011100111001100001
3100202120100210011220221
41133012112130321201
53133111134201423
6114524251003041
710243300603243
oct1370626347141
9322510704827
10102112022113
113a33a635622
1217959139481
13982424967a
144d2975a093
1529c9878e5d
hex17c659ce61

102112022113 has 2 divisors, whose sum is σ = 102112022114. Its totient is φ = 102112022112.

The previous prime is 102112022087. The next prime is 102112022137. The reversal of 102112022113 is 311220211201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98660694609 + 3451327504 = 314103^2 + 58748^2 .

It is an emirp because it is prime and its reverse (311220211201) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102112022113 is a prime.

It is not a weakly prime, because it can be changed into another prime (102112022153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51056011056 + 51056011057.

It is an arithmetic number, because the mean of its divisors is an integer number (51056011057).

Almost surely, 2102112022113 is an apocalyptic number.

It is an amenable number.

102112022113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102112022113 is an equidigital number, since it uses as much as digits as its factorization.

102112022113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 102112022113 its reverse (311220211201), we get a palindrome (413332233314).

The spelling of 102112022113 in words is "one hundred two billion, one hundred twelve million, twenty-two thousand, one hundred thirteen".