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10211211002017 is a prime number
BaseRepresentation
bin1001010010010111101110…
…0110101100000010100001
31100011011220211222211220201
42110211323212230002201
52314300030004031032
633414544321505201
72102510220263344
oct224457346540241
940134824884821
1010211211002017
11328760644aa43
12118b001aa2201
13590bb400bcac
1427432212845b
1512a93c7358e7
hex9497b9ac0a1

10211211002017 has 2 divisors, whose sum is σ = 10211211002018. Its totient is φ = 10211211002016.

The previous prime is 10211211001993. The next prime is 10211211002023. The reversal of 10211211002017 is 71020011211201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7086797706816 + 3124413295201 = 2662104^2 + 1767601^2 .

It is a cyclic number.

It is not a de Polignac number, because 10211211002017 - 27 = 10211211001889 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10211211001985 and 10211211002003.

It is not a weakly prime, because it can be changed into another prime (10211211002077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105605501008 + 5105605501009.

It is an arithmetic number, because the mean of its divisors is an integer number (5105605501009).

Almost surely, 210211211002017 is an apocalyptic number.

It is an amenable number.

10211211002017 is a deficient number, since it is larger than the sum of its proper divisors (1).

10211211002017 is an equidigital number, since it uses as much as digits as its factorization.

10211211002017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 10211211002017 its reverse (71020011211201), we get a palindrome (81231222213218).

The spelling of 10211211002017 in words is "ten trillion, two hundred eleven billion, two hundred eleven million, two thousand, seventeen".