Base | Representation |
---|---|
bin | 1001010010010111110110… |
… | …0001010000100110100001 |
3 | 1100011012000002110021210220 |
4 | 2110211331201100212201 |
5 | 2314300111220231340 |
6 | 33414551430313253 |
7 | 2102511060346602 |
oct | 224457541204641 |
9 | 40135002407726 |
10 | 10211243133345 |
11 | 32876225a6761 |
12 | 118b0107b8829 |
13 | 590bba87c107 |
14 | 2743264cdda9 |
15 | 12a940480ed0 |
hex | 9497d8509a1 |
10211243133345 has 64 divisors (see below), whose sum is σ = 17325253969920. Its totient is φ = 5117883711488.
The previous prime is 10211243133313. The next prime is 10211243133359. The reversal of 10211243133345 is 54333134211201.
It is a cyclic number.
It is not a de Polignac number, because 10211243133345 - 25 = 10211243133313 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 629421904 + ... + 629438126.
It is an arithmetic number, because the mean of its divisors is an integer number (270707093280).
Almost surely, 210211243133345 is an apocalyptic number.
10211243133345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
10211243133345 is a deficient number, since it is larger than the sum of its proper divisors (7114010836575).
10211243133345 is a wasteful number, since it uses less digits than its factorization.
10211243133345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19834.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 10211243133345 its reverse (54333134211201), we get a palindrome (64544377344546).
The spelling of 10211243133345 in words is "ten trillion, two hundred eleven billion, two hundred forty-three million, one hundred thirty-three thousand, three hundred forty-five".
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