Base | Representation |
---|---|
bin | 101111100011001101… |
… | …0101011101001011111 |
3 | 100202120102212112011122 |
4 | 1133012122223221133 |
5 | 3133111430143403 |
6 | 114524330441155 |
7 | 10243313202404 |
oct | 1370632535137 |
9 | 322512775148 |
10 | 102113131103 |
11 | 3a340222845 |
12 | 179595931bb |
13 | 9824547389 |
14 | 4d299682ab |
15 | 29c99e7838 |
hex | 17c66aba5f |
102113131103 has 4 divisors (see below), whose sum is σ = 104039794008. Its totient is φ = 100186468200.
The previous prime is 102113131031. The next prime is 102113131123. The reversal of 102113131103 is 301131311201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102113131103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102113131123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 963331373 + ... + 963331478.
It is an arithmetic number, because the mean of its divisors is an integer number (26009948502).
Almost surely, 2102113131103 is an apocalyptic number.
102113131103 is a deficient number, since it is larger than the sum of its proper divisors (1926662905).
102113131103 is an equidigital number, since it uses as much as digits as its factorization.
102113131103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1926662904.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 102113131103 its reverse (301131311201), we get a palindrome (403244442304).
The spelling of 102113131103 in words is "one hundred two billion, one hundred thirteen million, one hundred thirty-one thousand, one hundred three".
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