102113450143 has 4 divisors (see below), whose sum is σ = 102214254168. Its totient is φ = 102012646120.

The previous prime is 102113450123. The next prime is 102113450177. The reversal of 102113450143 is 341054311201.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341054311201 = 19793 ⋅17231057.

It is a cyclic number.

It is not a de Polignac number, because 102113450143 - 2⁵ = 102113450111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102113450123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50400493 + ... + 50402518.

It is an arithmetic number, because the mean of its divisors is an integer number (25553563542).

Almost surely, 2^102113450143 is an apocalyptic number.

102113450143 is a deficient number, since it is larger than the sum of its proper divisors (100804025).

102113450143 is a wasteful number, since it uses less digits than its factorization.

102113450143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100804024.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 102113450143 its reverse (341054311201), we get a palindrome (443167761344).

The spelling of 102113450143 in words is "one hundred two billion, one hundred thirteen million, four hundred fifty thousand, one hundred forty-three".