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102114241331 is a prime number
BaseRepresentation
bin101111100011001111…
…0111010101100110011
3100202120111221221010012
41133012132322230303
53133112221210311
6114524410325135
710243325505254
oct1370636725463
9322514857105
10102114241331
113a340910993
1217959a297ab
13982484580b
144d29b76b2b
1529c9b6678b
hex17c67bab33

102114241331 has 2 divisors, whose sum is σ = 102114241332. Its totient is φ = 102114241330.

The previous prime is 102114241319. The next prime is 102114241363. The reversal of 102114241331 is 133142411201.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102114241331 is a prime.

It is a super-3 number, since 3×1021142413313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 102114241297 and 102114241306.

It is not a weakly prime, because it can be changed into another prime (102114241631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51057120665 + 51057120666.

It is an arithmetic number, because the mean of its divisors is an integer number (51057120666).

Almost surely, 2102114241331 is an apocalyptic number.

102114241331 is a deficient number, since it is larger than the sum of its proper divisors (1).

102114241331 is an equidigital number, since it uses as much as digits as its factorization.

102114241331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 102114241331 its reverse (133142411201), we get a palindrome (235256652532).

The spelling of 102114241331 in words is "one hundred two billion, one hundred fourteen million, two hundred forty-one thousand, three hundred thirty-one".