102120000113 has 2 divisors, whose sum is σ = 102120000114. Its totient is φ = 102120000112.

The previous prime is 102120000109. The next prime is 102120000139. The reversal of 102120000113 is 311000021201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 72257740864 + 29862259249 = 268808^2 + 172807^2 .

It is a cyclic number.

It is not a de Polignac number, because 102120000113 - 2² = 102120000109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102120000094 and 102120000103.

It is not a weakly prime, because it can be changed into another prime (102120000163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51060000056 + 51060000057.

It is an arithmetic number, because the mean of its divisors is an integer number (51060000057).

Almost surely, 2^102120000113 is an apocalyptic number.

It is an amenable number.

102120000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102120000113 is an equidigital number, since it uses as much as digits as its factorization.

102120000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 102120000113 its reverse (311000021201), we get a palindrome (413120021314).

The spelling of 102120000113 in words is "one hundred two billion, one hundred twenty million, one hundred thirteen", and thus it is an aban number.