Base | Representation |
---|---|
bin | 1001010010011010101010… |
… | …1101001000010110011001 |
3 | 1100011020221220221002012011 |
4 | 2110212222231020112121 |
5 | 2314303134303014433 |
6 | 33415154550545521 |
7 | 2102535624106006 |
oct | 224465255102631 |
9 | 40136856832164 |
10 | 10212001219993 |
11 | 328798150a451 |
12 | 118b1a26682a1 |
13 | 590cab9485b1 |
14 | 2743990688ad |
15 | 12a986cc93cd |
hex | 949aab48599 |
10212001219993 has 2 divisors, whose sum is σ = 10212001219994. Its totient is φ = 10212001219992.
The previous prime is 10212001219957. The next prime is 10212001220011. The reversal of 10212001219993 is 39991210021201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10204363858329 + 7637361664 = 3194427^2 + 87392^2 .
It is a cyclic number.
It is not a de Polignac number, because 10212001219993 - 225 = 10211967665561 is a prime.
It is a super-3 number, since 3×102120012199933 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (10212001219093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106000609996 + 5106000609997.
It is an arithmetic number, because the mean of its divisors is an integer number (5106000609997).
Almost surely, 210212001219993 is an apocalyptic number.
It is an amenable number.
10212001219993 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212001219993 is an equidigital number, since it uses as much as digits as its factorization.
10212001219993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 40.
The spelling of 10212001219993 in words is "ten trillion, two hundred twelve billion, one million, two hundred nineteen thousand, nine hundred ninety-three".
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