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102121101121200 = 24352743311909091
BaseRepresentation
bin10111001110000011101011…
…111101001101011010110000
3111101120200102010021202001220
4113032003223331031122300
5101341123003341334300
61001105441453025040
730340002041165520
oct2716035375153260
9441520363252056
10102121101121200
112a5a23523227a7
12b553906185180
1344c9c94a48785
141b3098ad59680
15bc160e25ada0
hex5ce0ebf4d6b0

102121101121200 has 480 divisors, whose sum is σ = 383785420541952. Its totient is φ = 22725795456000.

The previous prime is 102121101121187. The next prime is 102121101121213. The reversal of 102121101121200 is 2121101121201.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (102121101121187) and next prime (102121101121213).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 102121101121200.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 111878655 + ... + 112787745.

Almost surely, 2102121101121200 is an apocalyptic number.

102121101121200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 102121101121200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (191892710270976).

102121101121200 is an abundant number, since it is smaller than the sum of its proper divisors (281664319420752).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

102121101121200 is a wasteful number, since it uses less digits than its factorization.

102121101121200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 909473 (or 909462 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 15.

Adding to 102121101121200 its reverse (2121101121201), we get a palindrome (104242202242401).

Subtracting from 102121101121200 its reverse (2121101121201), we obtain a palindrome (99999999999999).

The spelling of 102121101121200 in words is "one hundred two trillion, one hundred twenty-one billion, one hundred one million, one hundred twenty-one thousand, two hundred".