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102121134300 = 223252433497561
BaseRepresentation
bin101111100011011100…
…1001101100011011100
3100202120222221010111100
41133012321031203130
53133121002244200
6114525214153100
710243441214343
oct1370671154334
9322528833440
10102121134300
113a344799759
12179601b2790
1398260ba0b3
144d2aa4cb5a
1529ca578d00
hex17c6e4d8dc

102121134300 has 216 divisors, whose sum is σ = 328518990800. Its totient is φ = 26519270400.

The previous prime is 102121134289. The next prime is 102121134301. The reversal of 102121134300 is 3431121201.

102121134300 is a `hidden beast` number, since 1 + 0 + 21 + 211 + 3 + 430 + 0 = 666.

102121134300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102121134301) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 13502520 + ... + 13510080.

Almost surely, 2102121134300 is an apocalyptic number.

102121134300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 102121134300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164259495400).

102121134300 is an abundant number, since it is smaller than the sum of its proper divisors (226397856500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

102121134300 is a wasteful number, since it uses less digits than its factorization.

102121134300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7973 (or 7963 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 102121134300 its reverse (3431121201), we get a palindrome (105552255501).

The spelling of 102121134300 in words is "one hundred two billion, one hundred twenty-one million, one hundred thirty-four thousand, three hundred".