Base | Representation |
---|---|
bin | 111100110111101… |
… | …010110010010011 |
3 | 2122011121122220001 |
4 | 330313222302103 |
5 | 4042413214011 |
6 | 245200230431 |
7 | 34210164442 |
oct | 7467526223 |
9 | 2564548801 |
10 | 1021226131 |
11 | 484501342 |
12 | 24600b417 |
13 | 13375c723 |
14 | 998b4d59 |
15 | 5e9c57c1 |
hex | 3cdeac93 |
1021226131 has 2 divisors, whose sum is σ = 1021226132. Its totient is φ = 1021226130.
The previous prime is 1021226113. The next prime is 1021226179. The reversal of 1021226131 is 1316221201.
Together with previous prime (1021226113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1021226131 - 217 = 1021095059 is a prime.
It is a super-2 number, since 2×10212261312 = 2085805621274458322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1021226099 and 1021226108.
It is not a weakly prime, because it can be changed into another prime (1021226191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510613065 + 510613066.
It is an arithmetic number, because the mean of its divisors is an integer number (510613066).
Almost surely, 21021226131 is an apocalyptic number.
1021226131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021226131 is an equidigital number, since it uses as much as digits as its factorization.
1021226131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
The square root of 1021226131 is about 31956.6289054399. The cubic root of 1021226131 is about 1007.0258981482.
Adding to 1021226131 its reverse (1316221201), we get a palindrome (2337447332).
The spelling of 1021226131 in words is "one billion, twenty-one million, two hundred twenty-six thousand, one hundred thirty-one".
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