102123044132113 has 2 divisors, whose sum is σ = 102123044132114. Its totient is φ = 102123044132112.

The previous prime is 102123044132099. The next prime is 102123044132129. The reversal of 102123044132113 is 311231440321201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101620572974209 + 502471157904 = 10080703^2 + 708852^2 .

It is an emirp because it is prime and its reverse (311231440321201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102123044132113 - 2²¹ = 102123042034961 is a prime.

It is a super-3 number, since 3×102123044132113³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (102123944132113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51061522066056 + 51061522066057.

It is an arithmetic number, because the mean of its divisors is an integer number (51061522066057).

Almost surely, 2^{102123044132113} is an apocalyptic number.

It is an amenable number.

102123044132113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102123044132113 is an equidigital number, since it uses as much as digits as its factorization.

102123044132113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 102123044132113 its reverse (311231440321201), we get a palindrome (413354484453314).

The spelling of 102123044132113 in words is "one hundred two trillion, one hundred twenty-three billion, forty-four million, one hundred thirty-two thousand, one hundred thirteen".