10212314131 has 2 divisors, whose sum is σ = 10212314132. Its totient is φ = 10212314130.

The previous prime is 10212314053. The next prime is 10212314141. The reversal of 10212314131 is 13141321201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10212314131 - 2¹⁵ = 10212281363 is a prime.

It is a super-2 number, since 2×10212314131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10212314099 and 10212314108.

It is not a weakly prime, because it can be changed into another prime (10212314141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106157065 + 5106157066.

It is an arithmetic number, because the mean of its divisors is an integer number (5106157066).

Almost surely, 2^10212314131 is an apocalyptic number.

10212314131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10212314131 is an equidigital number, since it uses as much as digits as its factorization.

10212314131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10212314131 its reverse (13141321201), we get a palindrome (23353635332).

The spelling of 10212314131 in words is "ten billion, two hundred twelve million, three hundred fourteen thousand, one hundred thirty-one".