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1021244414143 = 5319268762531
BaseRepresentation
bin11101101110001101110…
…10010001100010111111
310121122000021112111000111
432313012322101202333
5113213002032223033
62101053032010451
7133532250202342
oct16670672214277
93548007474014
101021244414143
1136411a936758
12145b10830a27
13753c27186b5
14375ddb00459
151b8718927cd
hexedc6e918bf

1021244414143 has 4 divisors (see below), whose sum is σ = 1040513176728. Its totient is φ = 1001975651560.

The previous prime is 1021244414137. The next prime is 1021244414189. The reversal of 1021244414143 is 3414144421201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1021244414143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1021244414543) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9634381213 + ... + 9634381318.

It is an arithmetic number, because the mean of its divisors is an integer number (260128294182).

Almost surely, 21021244414143 is an apocalyptic number.

1021244414143 is a deficient number, since it is larger than the sum of its proper divisors (19268762585).

1021244414143 is an equidigital number, since it uses as much as digits as its factorization.

1021244414143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19268762584.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 1021244414143 its reverse (3414144421201), we get a palindrome (4435388835344).

The spelling of 1021244414143 in words is "one trillion, twenty-one billion, two hundred forty-four million, four hundred fourteen thousand, one hundred forty-three".

Divisors: 1 53 19268762531 1021244414143