Base | Representation |
---|---|
bin | 101111100011100100… |
… | …0100010110010100011 |
3 | 100202121021111022201111 |
4 | 1133013020202302203 |
5 | 3133123014402233 |
6 | 114525440244151 |
7 | 10243520324065 |
oct | 1370710426243 |
9 | 322537438644 |
10 | 102125153443 |
11 | 3a346a94365 |
12 | 17961610657 |
13 | 9826b965a1 |
14 | 4d2b3b7735 |
15 | 29caabeacd |
hex | 17c7222ca3 |
102125153443 has 2 divisors, whose sum is σ = 102125153444. Its totient is φ = 102125153442.
The previous prime is 102125153363. The next prime is 102125153447. The reversal of 102125153443 is 344351521201.
It is a strong prime.
It is an emirp because it is prime and its reverse (344351521201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 102125153443 - 233 = 93535218851 is a prime.
It is not a weakly prime, because it can be changed into another prime (102125153447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51062576721 + 51062576722.
It is an arithmetic number, because the mean of its divisors is an integer number (51062576722).
Almost surely, 2102125153443 is an apocalyptic number.
102125153443 is a deficient number, since it is larger than the sum of its proper divisors (1).
102125153443 is an equidigital number, since it uses as much as digits as its factorization.
102125153443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 102125153443 its reverse (344351521201), we get a palindrome (446476674644).
The spelling of 102125153443 in words is "one hundred two billion, one hundred twenty-five million, one hundred fifty-three thousand, four hundred forty-three".
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