1021300000033 has 2 divisors, whose sum is σ = 1021300000034. Its totient is φ = 1021300000032.

The previous prime is 1021299999983. The next prime is 1021300000037. The reversal of 1021300000033 is 3300000031201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 792272669409 + 229027330624 = 890097^2 + 478568^2 .

It is a cyclic number.

It is not a de Polignac number, because 1021300000033 - 2¹⁷ = 1021299868961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1021299999959 and 1021300000022.

It is not a weakly prime, because it can be changed into another prime (1021300000037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510650000016 + 510650000017.

It is an arithmetic number, because the mean of its divisors is an integer number (510650000017).

Almost surely, 2^{1021300000033} is an apocalyptic number.

It is an amenable number.

1021300000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1021300000033 is an equidigital number, since it uses as much as digits as its factorization.

1021300000033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 1021300000033 its reverse (3300000031201), we get a palindrome (4321300031234).

The spelling of 1021300000033 in words is "one trillion, twenty-one billion, three hundred million, thirty-three", and thus it is an aban number.