102130011312 has 320 divisors, whose sum is σ = 324309242880. Its totient is φ = 27074138112.

The previous prime is 102130011301. The next prime is 102130011353. The reversal of 102130011312 is 213110031201.

It is a happy number.

It is a super-3 number, since 3×102130011312³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 102130011291 and 102130011300.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 29922118 + ... + 29925530.

It is an arithmetic number, because the mean of its divisors is an integer number (1013466384).

Almost surely, 2^102130011312 is an apocalyptic number.

102130011312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 102130011312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (162154621440).

102130011312 is an abundant number, since it is smaller than the sum of its proper divisors (222179231568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

102130011312 is a wasteful number, since it uses less digits than its factorization.

102130011312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3580 (or 3574 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 102130011312 its reverse (213110031201), we get a palindrome (315240042513).

The spelling of 102130011312 in words is "one hundred two billion, one hundred thirty million, eleven thousand, three hundred twelve".