Base | Representation |
---|---|
bin | 1001010010011110100011… |
… | …0111000100010101110011 |
3 | 1100011100122121010102110021 |
4 | 2110213220313010111303 |
5 | 2314312303231344103 |
6 | 33415450241344311 |
7 | 2102603515515061 |
oct | 224475067042563 |
9 | 40140577112407 |
10 | 10213044012403 |
11 | 3288367100861 |
12 | 118b433938097 |
13 | 5911169b931b |
14 | 274457755031 |
15 | 12a9e860ebbd |
hex | 949e8dc4573 |
10213044012403 has 32 divisors (see below), whose sum is σ = 10595081871360. Its totient is φ = 9840094306560.
The previous prime is 10213044012329. The next prime is 10213044012419. The reversal of 10213044012403 is 30421044031201.
10213044012403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 10213044012403 - 213 = 10213044004211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10213044012473) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1226198743 + ... + 1226207071.
It is an arithmetic number, because the mean of its divisors is an integer number (331096308480).
Almost surely, 210213044012403 is an apocalyptic number.
10213044012403 is a deficient number, since it is larger than the sum of its proper divisors (382037858957).
10213044012403 is a wasteful number, since it uses less digits than its factorization.
10213044012403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10507.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 10213044012403 its reverse (30421044031201), we get a palindrome (40634088043604).
The spelling of 10213044012403 in words is "ten trillion, two hundred thirteen billion, forty-four million, twelve thousand, four hundred three".
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