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102131099977 is a prime number
BaseRepresentation
bin101111100011101111…
…1001110100101001001
3100202121200200102211111
41133013133032211021
53133131030144402
6114530211530321
710243622011654
oct1370737164511
9322550612744
10102131099977
113a34a386055
12179635b99a1
13982819914a
144d2c0c489b
1529cb3969d7
hex17c77ce949

102131099977 has 2 divisors, whose sum is σ = 102131099978. Its totient is φ = 102131099976.

The previous prime is 102131099953. The next prime is 102131100017. The reversal of 102131099977 is 779990131201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91967234121 + 10163865856 = 303261^2 + 100816^2 .

It is an emirp because it is prime and its reverse (779990131201) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102131099977 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 102131099977.

It is not a weakly prime, because it can be changed into another prime (102131099677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51065549988 + 51065549989.

It is an arithmetic number, because the mean of its divisors is an integer number (51065549989).

Almost surely, 2102131099977 is an apocalyptic number.

It is an amenable number.

102131099977 is a deficient number, since it is larger than the sum of its proper divisors (1).

102131099977 is an equidigital number, since it uses as much as digits as its factorization.

102131099977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 214326, while the sum is 49.

The spelling of 102131099977 in words is "one hundred two billion, one hundred thirty-one million, ninety-nine thousand, nine hundred seventy-seven".