10213131113 has 2 divisors, whose sum is σ = 10213131114. Its totient is φ = 10213131112.

The previous prime is 10213131091. The next prime is 10213131121. The reversal of 10213131113 is 31113131201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5195958889 + 5017172224 = 72083^2 + 70832^2 .

It is a cyclic number.

It is not a de Polignac number, because 10213131113 - 2¹⁰ = 10213130089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10213131091 and 10213131100.

It is not a weakly prime, because it can be changed into another prime (10213131143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106565556 + 5106565557.

It is an arithmetic number, because the mean of its divisors is an integer number (5106565557).

Almost surely, 2^10213131113 is an apocalyptic number.

It is an amenable number.

10213131113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10213131113 is an equidigital number, since it uses as much as digits as its factorization.

10213131113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10213131113 its reverse (31113131201), we get a palindrome (41326262314).

The spelling of 10213131113 in words is "ten billion, two hundred thirteen million, one hundred thirty-one thousand, one hundred thirteen".