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1021314313147 is a prime number
BaseRepresentation
bin11101101110010110001…
…00111010101110111011
310121122012011001201102111
432313023010322232323
5113213122431010042
62101104010113151
7133534056265462
oct16671304725673
93548164051374
101021314313147
11364156338927
12145b3011b7b7
137540405025b
14376090d79d9
151b877a9d517
hexedcb13abbb

1021314313147 has 2 divisors, whose sum is σ = 1021314313148. Its totient is φ = 1021314313146.

The previous prime is 1021314313109. The next prime is 1021314313153. The reversal of 1021314313147 is 7413134131201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1021314313147 - 215 = 1021314280379 is a prime.

It is not a weakly prime, because it can be changed into another prime (1021374313147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510657156573 + 510657156574.

It is an arithmetic number, because the mean of its divisors is an integer number (510657156574).

Almost surely, 21021314313147 is an apocalyptic number.

1021314313147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1021314313147 is an equidigital number, since it uses as much as digits as its factorization.

1021314313147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 1021314313147 its reverse (7413134131201), we get a palindrome (8434448444348).

The spelling of 1021314313147 in words is "one trillion, twenty-one billion, three hundred fourteen million, three hundred thirteen thousand, one hundred forty-seven".