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10213153681 is a prime number
BaseRepresentation
bin10011000001100000…
…00101101110010001
3222100202211222000011
421200300011232101
5131404031404211
64405235154521
7511043242153
oct114060055621
928322758004
1010213153681
114371071585
121b90445a41
13c69bcb903
146cc5aaad3
153eb964921
hex260c05b91

10213153681 has 2 divisors, whose sum is σ = 10213153682. Its totient is φ = 10213153680.

The previous prime is 10213153673. The next prime is 10213153711. The reversal of 10213153681 is 18635131201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9788134225 + 425019456 = 98935^2 + 20616^2 .

It is a cyclic number.

It is not a de Polignac number, because 10213153681 - 23 = 10213153673 is a prime.

It is a super-2 number, since 2×102131536812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10213153781) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106576840 + 5106576841.

It is an arithmetic number, because the mean of its divisors is an integer number (5106576841).

Almost surely, 210213153681 is an apocalyptic number.

It is an amenable number.

10213153681 is a deficient number, since it is larger than the sum of its proper divisors (1).

10213153681 is an equidigital number, since it uses as much as digits as its factorization.

10213153681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 31.

Adding to 10213153681 its reverse (18635131201), we get a palindrome (28848284882).

The spelling of 10213153681 in words is "ten billion, two hundred thirteen million, one hundred fifty-three thousand, six hundred eighty-one".