Base | Representation |
---|---|
bin | 101111100011110011… |
… | …0011110011101000011 |
3 | 100202121211020222011211 |
4 | 1133013212132131003 |
5 | 3133132022000003 |
6 | 114530320350551 |
7 | 10243644114256 |
oct | 1370746363503 |
9 | 322554228154 |
10 | 102133000003 |
11 | 3a350463621 |
12 | 17964175457 |
13 | 98286b2c18 |
14 | 4d2c45b09d |
15 | 29cb61e96d |
hex | 17c799e743 |
102133000003 has 2 divisors, whose sum is σ = 102133000004. Its totient is φ = 102133000002.
The previous prime is 102132999977. The next prime is 102133000031. The reversal of 102133000003 is 300000331201.
It is a weak prime.
It is an emirp because it is prime and its reverse (300000331201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 102133000003 - 29 = 102132999491 is a prime.
It is a super-2 number, since 2×1021330000032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (102133000063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51066500001 + 51066500002.
It is an arithmetic number, because the mean of its divisors is an integer number (51066500002).
Almost surely, 2102133000003 is an apocalyptic number.
102133000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
102133000003 is an equidigital number, since it uses as much as digits as its factorization.
102133000003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 102133000003 its reverse (300000331201), we get a palindrome (402133331204).
The spelling of 102133000003 in words is "one hundred two billion, one hundred thirty-three million, three", and thus it is an aban number.
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