Base | Representation |
---|---|
bin | 101111100011110011… |
… | …0111010000111110101 |
3 | 100202121211110201122020 |
4 | 1133013212322013311 |
5 | 3133132034111313 |
6 | 114530323023353 |
7 | 10243645065546 |
oct | 1370746720765 |
9 | 322554421566 |
10 | 102133113333 |
11 | 3a350530789 |
12 | 1796420ab59 |
13 | 9828722694 |
14 | 4d2c48a4cd |
15 | 29cb643323 |
hex | 17c79ba1f5 |
102133113333 has 4 divisors (see below), whose sum is σ = 136177484448. Its totient is φ = 68088742220.
The previous prime is 102133113311. The next prime is 102133113373. The reversal of 102133113333 is 333311331201.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 102133113333 - 210 = 102133112309 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102133113373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17022185553 + ... + 17022185558.
It is an arithmetic number, because the mean of its divisors is an integer number (34044371112).
Almost surely, 2102133113333 is an apocalyptic number.
It is an amenable number.
102133113333 is a deficient number, since it is larger than the sum of its proper divisors (34044371115).
102133113333 is an equidigital number, since it uses as much as digits as its factorization.
102133113333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34044371114.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 102133113333 its reverse (333311331201), we get a palindrome (435444444534).
The spelling of 102133113333 in words is "one hundred two billion, one hundred thirty-three million, one hundred thirteen thousand, three hundred thirty-three".
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