Base | Representation |
---|---|
bin | 1001010010011111100011… |
… | …1101011111010100000000 |
3 | 1100011101100102101212210011 |
4 | 2110213320331133110000 |
5 | 2314313331404144300 |
6 | 33415533131114304 |
7 | 2102613305502325 |
oct | 224477075372400 |
9 | 40141312355704 |
10 | 10213314131200 |
11 | 3288495626034 |
12 | 118b4aa2a2994 |
13 | 59115a95422b |
14 | 27448158ab4c |
15 | 12aa121b9eba |
hex | 949f8f5f500 |
10213314131200 has 216 divisors, whose sum is σ = 25747206101120. Its totient is φ = 4010027212800.
The previous prime is 10213314131117. The next prime is 10213314131263. The reversal of 10213314131200 is 213141331201.
10213314131200 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×102133141312002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 190097941 + ... + 190151659.
Almost surely, 210213314131200 is an apocalyptic number.
10213314131200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 10213314131200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (12873603050560).
10213314131200 is an abundant number, since it is smaller than the sum of its proper divisors (15533891969920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10213314131200 is an equidigital number, since it uses as much as digits as its factorization.
10213314131200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54293 (or 54274 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 10213314131200 its reverse (213141331201), we get a palindrome (10426455462401).
It can be divided in two parts, 10213 and 314131200, that added together give a palindrome (314141413).
The spelling of 10213314131200 in words is "ten trillion, two hundred thirteen billion, three hundred fourteen million, one hundred thirty-one thousand, two hundred".
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