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102134134042 = 2372713701923
BaseRepresentation
bin101111100011110101…
…0110011010100011010
3100202121220101120210021
41133013222303110122
53133132314242132
6114530400541054
710243656546433
oct1370752632432
9322556346707
10102134134042
113a351068646
121796462178a
1398289bc155
144d2c67448a
1529cb795997
hex17c7ab351a

102134134042 has 8 divisors (see below), whose sum is σ = 153242318016. Its totient is φ = 51053361372.

The previous prime is 102134134031. The next prime is 102134134043. The reversal of 102134134042 is 240431431201.

102134134042 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1021341340423 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 102134133998 and 102134134016.

It is not an unprimeable number, because it can be changed into a prime (102134134043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6843508 + ... + 6858415.

It is an arithmetic number, because the mean of its divisors is an integer number (19155289752).

Almost surely, 2102134134042 is an apocalyptic number.

102134134042 is a deficient number, since it is larger than the sum of its proper divisors (51108183974).

102134134042 is a wasteful number, since it uses less digits than its factorization.

102134134042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13705652.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 102134134042 its reverse (240431431201), we get a palindrome (342565565243).

The spelling of 102134134042 in words is "one hundred two billion, one hundred thirty-four million, one hundred thirty-four thousand, forty-two".

Divisors: 1 2 3727 7454 13701923 27403846 51067067021 102134134042