102141020131 has 2 divisors, whose sum is σ = 102141020132. Its totient is φ = 102141020130.

The previous prime is 102141020087. The next prime is 102141020153. The reversal of 102141020131 is 131020141201.

It is a strong prime.

It is an emirp because it is prime and its reverse (131020141201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102141020131 - 2¹³ = 102141011939 is a prime.

It is a super-2 number, since 2×102141020131² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (102141080131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51070510065 + 51070510066.

It is an arithmetic number, because the mean of its divisors is an integer number (51070510066).

Almost surely, 2^102141020131 is an apocalyptic number.

102141020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

102141020131 is an equidigital number, since it uses as much as digits as its factorization.

102141020131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 102141020131 its reverse (131020141201), we get a palindrome (233161161332).

The spelling of 102141020131 in words is "one hundred two billion, one hundred forty-one million, twenty thousand, one hundred thirty-one".