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102141221142551 = 605584316866557
BaseRepresentation
bin10111001110010110011011…
…001101000000000000010111
3111101122121100022122201122212
4113032112123031000000113
5101341440210103030201
61001123010150544035
730341313451433063
oct2716263315000027
9441577308581585
10102141221142551
112a5aa937578618
12b5577a036801b
1344cbb50256c56
141b31939164aa3
15bc1dda7d3abb
hex5ce59b340017

102141221142551 has 4 divisors (see below), whose sum is σ = 102141244064952. Its totient is φ = 102141198220152.

The previous prime is 102141221142503. The next prime is 102141221142581. The reversal of 102141221142551 is 155241122141201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 102141221142551 - 218 = 102141220880407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102141221142581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2377436 + ... + 14489121.

It is an arithmetic number, because the mean of its divisors is an integer number (25535311016238).

Almost surely, 2102141221142551 is an apocalyptic number.

102141221142551 is a deficient number, since it is larger than the sum of its proper divisors (22922401).

102141221142551 is an equidigital number, since it uses as much as digits as its factorization.

102141221142551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22922400.

The product of its (nonzero) digits is 6400, while the sum is 32.

Adding to 102141221142551 its reverse (155241122141201), we get a palindrome (257382343283752).

The spelling of 102141221142551 in words is "one hundred two trillion, one hundred forty-one billion, two hundred twenty-one million, one hundred forty-two thousand, five hundred fifty-one".

Divisors: 1 6055843 16866557 102141221142551