Base | Representation |
---|---|
bin | 10111001110010110011011… |
… | …110010100111101011110011 |
3 | 111101122121101000012202120122 |
4 | 113032112123302213223303 |
5 | 101341440220114120103 |
6 | 1001123011142200455 |
7 | 30341313631315613 |
oct | 2716263362475363 |
9 | 441577330182518 |
10 | 102141231004403 |
11 | 2a5aa9420a3a08 |
12 | b5577a372312b |
13 | 44cbb522ca976 |
14 | 1b3193a5b0a43 |
15 | bc1ddb5d0b38 |
hex | 5ce59bca7af3 |
102141231004403 has 2 divisors, whose sum is σ = 102141231004404. Its totient is φ = 102141231004402.
The previous prime is 102141231004367. The next prime is 102141231004451. The reversal of 102141231004403 is 304400132141201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 102141231004403 - 210 = 102141231003379 is a prime.
It is not a weakly prime, because it can be changed into another prime (102141231004303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51070615502201 + 51070615502202.
It is an arithmetic number, because the mean of its divisors is an integer number (51070615502202).
Almost surely, 2102141231004403 is an apocalyptic number.
102141231004403 is a deficient number, since it is larger than the sum of its proper divisors (1).
102141231004403 is an equidigital number, since it uses as much as digits as its factorization.
102141231004403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 102141231004403 its reverse (304400132141201), we get a palindrome (406541363145604).
The spelling of 102141231004403 in words is "one hundred two trillion, one hundred forty-one billion, two hundred thirty-one million, four thousand, four hundred three".
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