Base | Representation |
---|---|
bin | 10011000001101010… |
… | …11110011100100011 |
3 | 222100212111200212221 |
4 | 21200311132130203 |
5 | 131404412100132 |
6 | 4405325331511 |
7 | 511061242555 |
oct | 114065363443 |
9 | 28325450787 |
10 | 10214565667 |
11 | 4371946409 |
12 | 1b90a06b97 |
13 | c6a2a44c7 |
14 | 6cc8574d5 |
15 | 3ebb42e97 |
hex | 260d5e723 |
10214565667 has 2 divisors, whose sum is σ = 10214565668. Its totient is φ = 10214565666.
The previous prime is 10214565659. The next prime is 10214565671. The reversal of 10214565667 is 76656541201.
10214565667 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10214565667 - 23 = 10214565659 is a prime.
It is not a weakly prime, because it can be changed into another prime (10214565637) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5107282833 + 5107282834.
It is an arithmetic number, because the mean of its divisors is an integer number (5107282834).
Almost surely, 210214565667 is an apocalyptic number.
10214565667 is a deficient number, since it is larger than the sum of its proper divisors (1).
10214565667 is an equidigital number, since it uses as much as digits as its factorization.
10214565667 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 10214565667 in words is "ten billion, two hundred fourteen million, five hundred sixty-five thousand, six hundred sixty-seven".
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