Base | Representation |
---|---|
bin | 11101101110101100000… |
… | …10001100110000010011 |
3 | 10121122122221222121001101 |
4 | 32313112002030300103 |
5 | 113214012011244112 |
6 | 2101134134245231 |
7 | 133541451003634 |
oct | 16672602146023 |
9 | 3548587877041 |
10 | 1021498149907 |
11 | 364240091134 |
12 | 145b817b6817 |
13 | 754331685c1 |
14 | 376256ad88b |
15 | 1b888cb3757 |
hex | edd608cc13 |
1021498149907 has 2 divisors, whose sum is σ = 1021498149908. Its totient is φ = 1021498149906.
The previous prime is 1021498149901. The next prime is 1021498149929. The reversal of 1021498149907 is 7099418941201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1021498149907 - 215 = 1021498117139 is a prime.
It is not a weakly prime, because it can be changed into another prime (1021498149901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510749074953 + 510749074954.
It is an arithmetic number, because the mean of its divisors is an integer number (510749074954).
Almost surely, 21021498149907 is an apocalyptic number.
1021498149907 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021498149907 is an equidigital number, since it uses as much as digits as its factorization.
1021498149907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1306368, while the sum is 55.
The spelling of 1021498149907 in words is "one trillion, twenty-one billion, four hundred ninety-eight million, one hundred forty-nine thousand, nine hundred seven".
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