Base | Representation |
---|---|
bin | 11101101111101001001… |
… | …10011111010001101001 |
3 | 10121200222200222000220112 |
4 | 32313310212133101221 |
5 | 113221034302320213 |
6 | 2101301054104105 |
7 | 133560245663513 |
oct | 16676446372151 |
9 | 3550880860815 |
10 | 1022010979433 |
11 | 364483610594 |
12 | 1460a54ab035 |
13 | 754b5493122 |
14 | 37673844bb3 |
15 | 1b8b8d12ea8 |
hex | edf499f469 |
1022010979433 has 2 divisors, whose sum is σ = 1022010979434. Its totient is φ = 1022010979432.
The previous prime is 1022010979421. The next prime is 1022010979447. The reversal of 1022010979433 is 3349790102201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 837569075344 + 184441904089 = 915188^2 + 429467^2 .
It is a cyclic number.
It is not a de Polignac number, because 1022010979433 - 28 = 1022010979177 is a prime.
It is not a weakly prime, because it can be changed into another prime (1022010979403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 511005489716 + 511005489717.
It is an arithmetic number, because the mean of its divisors is an integer number (511005489717).
Almost surely, 21022010979433 is an apocalyptic number.
It is an amenable number.
1022010979433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1022010979433 is an equidigital number, since it uses as much as digits as its factorization.
1022010979433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 41.
The spelling of 1022010979433 in words is "one trillion, twenty-two billion, ten million, nine hundred seventy-nine thousand, four hundred thirty-three".
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